Imagine that the Big Dipper crosses the meridian, the point straight overhead, at about 10:00 pm tonight. Where will the big dipper be in the sky at 1:00 am tonight?

Imagine that the Big Dipper crosses the meridian, the point straight overhead, at about 10:00 pm tonight. Where will the big dipper be in the sky at 1:00 am tonight?



A) 1/4 of the way from a point overhead to the western horizon
B) Halfway from a point overhead to the W horizon
C) 15 degrees from a point overhead to the W horizon
DD 30 degrees from a point overhead to the W horizon
E) Setting on the W horizon


Answer: E

Imagine that the Big Sipper crosses the meridian, the point straight overhead, at about 10:00 pm tonight, Where will be Dipper be in the sky at 1:00 am tonight?

Imagine that the Big Sipper crosses the meridian, the point straight overhead, at about 10:00 pm tonight, Where will be Dipper be in the sky at 1:00 am tonight?



A) One fourth of the way from a point overhead to the western horizon
B) Halfway from a point overhead to the W horizon
C) 15 degrees from a point overhead to the W horizon
D) 30 degrees from a point overhead to the W horizon
E) Setting on the W horizon


Answer: E

Why is the sky coordinate right ascension (RA) referenced to 1950.0 AD in most star atlases?

Why is the sky coordinate right ascension (RA) referenced to 1950.0 AD in most star atlases?




A) Celestial coordinates were first conceived by astronomers who worked in the middle of the 20th century and they decided the year 1950 was convenient
B) 1950 was the year that lateral stellar motion was discovered
C) The phenomenon of precession shifts the zero of RA over time
D) Telescopes were first constructed with hour circles and RA dials in the year 1950
E) 1950 was the year that telescopes improved to the point that astronomers could measure small shifts in the celestial sphere


Answer: B

The moon lies 384,000 km from Earth, and the Sun lies 150,000,000 km away. If both have the same angular size as seen from Earth, how many times larger (in diameter) than the Moon is the Sun?

The moon lies 384,000 km from Earth, and the Sun lies 150,000,000 km away. If both have the same angular size as seen from Earth, how many times larger (in diameter) than the Moon is the Sun?



A) 93 million
B) 227
C) 1029
D) 391
E) cannot answer with more info


Answer: E

The last quarter phase of the Moon:

The last quarter phase of the Moon:




A) Rises at sunrise
B) Sets at sunrise
C) Crosses the meridian at sunrise
D) Rises at sunset
E) Sets at sunset


Answer: D

Why is there a two day difference the sidereal and synodic months?

Why is there a two day difference the sidereal and synodic months?



A) The moon speedup at perigee, and slows down at apogee
B) The sidereal day is four minutes shorter than the solar day, and it adds up
C) The Earth is closer to the Sun during the sidereal month
D) The Earth is also revolving around the Sun, so the Moon must "catch up"
E) The Muslim lunar year is only 354 days long, on average


Answer: D

Which statement about the first quarter moon is FALSE?

Which statement about the first quarter moon is FALSE?




A) It rises about noon
B) From the Earth, its appears 25% sunlit
C) It is the half moon of the evening sky
D) It is highest in the sky at sunset
E) It occurs about a week after new moon


Answer: B

Which statement about the ecliptic is false?

Which statement about the ecliptic is false?




A) The sun appears to move about a degree per day eastward long it
B) It is tilted 23.5 degrees with respect to the equator
C) The year is marked by the sun's return to the same place along ti
D) The moon can never leave it, but moves twelve times faster than the sun
E) the major planets stay close to it, but not always on it


Answer: A

From a location in the United States of America, a star is observed to be rising due East. Where will this star be located 6 hours later?

From a location in the United States of America, a star is observed to be rising due East. Where will this star be located 6 hours later?



A) Directly overhead
B) High in the northern sky
C) high in the southern sky
D) setting due west
E) the location of the star cannot be determined from the info given


Answer: D

Considering the Moon's phases, everyone on Earth sees

Considering the Moon's phases, everyone on Earth sees




A) The same phase in 24 hours
B) Different phases in 24 hours
C) A lunar eclipse once a month
D) Different sides of the Moon


Answer: A

What causes Earth's seasons?

What causes Earth's seasons?



A) Earth's rotation axis wobbles
B) The greenhouse effect
C) Earth's rotational axis is tilted 23.5 degrees
D) Earth moves closer or father from the Sun
E) global warming and cooling


Answer: C

In a spectroscopic binary system, the star showing the larger blue shift is:

In a spectroscopic binary system, the star showing the larger blue shift is:



A) Cooler and receding the fastest
B) Less massive of the pair and receding slower
C) More massive and approaching us
D) Less massive and approaching us at this moment
E) Hotter and receding faster


Answer: D

In comparing first magnitude Deneb with second magnitude Polaris, we find that:

In comparing first magnitude Deneb with second magnitude Polaris, we find that:




A) Polaris is in reality much more luminous
B) Deneb must be much hotter than Polaris
C) Deneb appears 2.5 times brighter to us than does Polaris
D) Polaris is really 100 times brighter than nearby Deneb
E) Deneb is really much closer than Polaris


Answer: C

In the proton-proton cycle, the helium atom and neutrino have less mass than the original hydrogen. What happens to the "lost" mass?

In the proton-proton cycle, the helium atom and neutrino have less mass than the original hydrogen. What happens to the "lost" mass?



A) It is recycled back into hydrogen
B) It is ejected into space
C) It is converted to energy
D) It is transformed into electrons
E) Conservation of mass dictates no mass can be lost


Answer: C

During a period of high solar activity, the corona:

During a period of high solar activity, the corona:




A) Disappears
B) Is more irregular
C) Cools almost to the temperature of the photosphere
D) Becomes smooth and even
E) Shrinks to half its normal size


Answer: B

How would sunspots appear if you could magically remove them from the Sun?

How would sunspots appear if you could magically remove them from the Sun?




A) They would appear blue-white, like Sirius but brighter
B) Because sunspots are dark spots, they would be invisible against the blackness of space
C) They would shine bright orange in color, like Arcturus
D) They would not appear any differently than on the surface of the Sun
E) They would shine only with reflected sunlight, appearing similar to Venus


Answer: C

What is it about the Sun's corona that astronomers don't understand?

What is it about the Sun's corona that astronomers don't understand?




A) No ne knows why that part of the Sun's atmosphere does not drift away into space
B) During total solar eclipses, the corona sometimes disappears from view
C) The corner seems to absorb 2/3 of the neutrinos that pass through it
D) The corona is much hotter than layers of the Sun that are closer to the solar interior
E) The Sun's corona extends to the outer reaches of the solar system


Answer: D

Star A has an absolute magnitude of 2.5 and star B has an apparent magnitude of 2.5, but star A is a main sequence star and star B is a red giant. Which statement below is correct?

Star A has an absolute magnitude of 2.5 and star B has an apparent magnitude of 2.5, but star A is a main sequence star and star B is a red giant. Which statement below is correct?




A) Star A appears brighter than star B, but actually star B and star A are the same brightness.
B) Star B appears brighter than star A, but actually star B and star A are the same brightness.
C) Star A and star B appear to have the same brightness, but actually star B is brighter than star A.
D) Star A and star B appear to have the same brightness, but actually star A is brighter than star B.
E) It is impossible to determine how bright these stars are or appear to be relative to one another, given the information above.


Answer: E

In general, the narrower the spectral line of a star:

In general, the narrower the spectral line of a star:




A) The cooler the star is
B) The denser the star is
C) The hotter the star is
D) The smaller the star is
E) The bigger the star is


Answer: E

Figure 17.15 in the textbook ("H-R Diagram of Bright Stars") shows Vega and Arcturus at approximately the same level on the vertical axis. This means that Arcturus must be

Figure 17.15 in the textbook ("H-R Diagram of Bright Stars") shows Vega and Arcturus at approximately the same level on the vertical axis. This means that Arcturus must be




A) Hotter than Vega
B) Larger than Vega
C) Of the same spectral class as Vega
D) Fainter than Vega


Answer: B

Two red stars have surface temperatures of 3000 K, but Star A's luminosity is about 5% of the Sun's and Star B's luminosity is about 32,000 times the luminosity of the Sun. How much bigger is star B than star A?

Two red stars have surface temperatures of 3000 K, but Star A's luminosity is about 5% of the Sun's and Star B's luminosity is about 32,000 times the luminosity of the Sun. How much bigger is star B than star A?



A) Star B's radius is about 800 times larger than star A's radius.
B) Star B's radius is about 16 times larger than star A's radius.
C) They are the same size.
D) Star B's radius is about 640,000 times larger than star A's radius.
E) This cannot be determined from the information given.


Answer: A

What is proper motion?

What is proper motion?



A) It is the annual apparent motion of a star across the sky.
B) It is the motion of a star towards or away from us, revealed by Doppler shifts.
C) It is the orbital motion of a star around the Galaxy.
D) It is the apparent shift as we go to opposite sides of our orbit every six months.
E) It is the true, not apparent, motion of a star in space.


Answer: A

The mass of a star may be determined

The mass of a star may be determined



A) By studying its orbit around a binary companion
B) By determining its composition
C) By measuring its Doppler shift
D) By measuring its luminosity


Answer: A

Stars of spectral class M do not show strong lines of hydrogen in their spectra because

Stars of spectral class M do not show strong lines of hydrogen in their spectra because




A) Their surfaces are so hot that most hydrogen is ionized
B) Their surfaces are so cool that most hydrogen is in the ground state
C) They contain very little hydrogen
D) They hydrogen lines are swamped by even stronger lines of other elements


Answer: B

Two stars--A, with a luminosity 0.5 times that of the Sun, and B, with a luminosity 4.5 times that of the Sun--are observed to have the same apparent brightness, Which one is more distant?

Two stars--A, with a luminosity 0.5 times that of the Sun, and B, with a luminosity 4.5 times that of the Sun--are observed to have the same apparent brightness, Which one is more distant?




A) Star A
B) Star B
C) Cannot determine without more data


Answer: B

On the H-R diagram, red supergiants like Betelgeuse lie:

On the H-R diagram, red supergiants like Betelgeuse lie:




A) At the bottom left
B) At the bottom right
C) At the top left
D) At the top right
E) They can't be plotted, for they are not main sequence


Answer: D

A star that is cool and very luminous must have

A star that is cool and very luminous must have




A) A very large radius
B) A very small radius
C) A very small mass
D) A very great distance
E) A very low velocity


Answer: A

Using the radius-luminosity-temperature relationship, estimate the size of the star Sirius B using the fact that the temperature of Sirius B is 12,000 K and its luminosity is 10(24) W, about 0.002 times the Sun

Using the radius-luminosity-temperature relationship, estimate the size of the star Sirius B using the fact that the temperature of Sirius B is 12,000 K and its luminosity is 10(24) W, about 0.002 times the Sun




A) 10 Rsun
B) 100 Rsun
C) 0.1 Rsun
D) 0.01 Rsun
E) 0.001 Rsun


Answer: D

Star A and star B both have an apparent magnitude of 4.0, but star A has an absolute magnitude of 1.0 and star B has an absolute magnitude of 7.0. Which statement below is correct?

Star A and star B both have an apparent magnitude of 4.0, but star A has an absolute magnitude of 1.0 and star B has an absolute magnitude of 7.0. Which statement below is correct?




A) Star A appears brighter than star B, but actually star B and star A are the same brightness
B) Star B appears brighter than Star A, but actually star B and star A are the same brightness
C) Star A and star B appear to have the same brightness, but actually star B is brighter than star A
D) Star A and star B appear to have the same brightness, but actually star A is brighter than star B
E) It is impossible to determine how bright these stars are or appear to be relative to one another, given the info above


Answer: D

A white dwarf can explode when

A white dwarf can explode when



a) its mass exceeds the Chandrasekhar limit
b) its electron degeneracy increases enormously
c) fusion reactions increase in its core
d) iron in its core collapses
e) the planetary nebula stage ends


Answer: a) its mass exceeds the Chandrasekhar limit

Elements heavier than carbon(hydrogen/helium) were created

Elements heavier than carbon(hydrogen/helium) were created 



a) in the Big Bang
b) by the nucleosynthesis in a massive star
c) in the cores of stars like the sun
d) within planetary nebula
e) they have always existed


Answer: b) by nucleosynthesis in massive stars
Stars the size of our sun do not produce elements heavier than carbon.

The sun will evolve away from the main sequence when

The sun will evolve away from the main sequence when



a) its core begins fusing iron
b) its supply of hydrogen
c) the carbon core detonates, and it explodes as a type I supernova
d) helium builds up in the core, while the hydrogen- burning shell expands
e) the core loses all of its neutrinos, so all fusion cease


Answer: d) helium builds up in the core, while the hydrogen- burning shell expands

What is a T-Tauri star?

What is a T-Tauri star?


a) a collapsing cloud of gas about to become a protostar
b) a dying star
c) a cool main sequence star
d) a star releasing a planetary nebula
e) a protostar about to become a star


Answer: E) a protostar about to become a star

t-tauri stars often show jets of gas emitted in two direction - "bi-polar flow" suggesting they are not yet stable

Most of the carbon in our bodies originated in

Most of the carbon in our bodies originated in 



a) a nearby galaxy
b) the core of the sun
c) the core of a red giant star
d) a supernova


Answer: c) the core of a red giant star

The red glow of an emission nebula

The red glow of an emission nebula 



a) is a reflection of light from stars near the nebula.
b) is the unresolved light of many faint red stars within the nebula.
c) is emitted by warm gas falling onto the stars at the center.
d) is produced by hydrogen gas heated to high temperatures by massive stars within the nebula.


Answer: d) is produced by hydrogen gas heated to high temperatures by massive stars within the nebula.

The mass of a star may be determined

The mass of a star may be determined 




a) by studying its orbit around a binary companion.
b) by measuring its luminosity.
c) by determining its composition.
d) by measuring its Doppler shift.


Answer: a) by studying its orbit around a binary companion

Stars of spectral class M do not show strong lines of hydrogen in their spectra because

Stars of spectral class M do not show strong lines of hydrogen in their spectra because




a) the hydrogen lines are swamped by even stronger lines of other elements.
b) they contain very little hydrogen.
c) their surfaces are so hot that most hydrogen is ionized.
d) their surfaces are so cool that most hydrogen is in the ground state.


Answer: d) their surfaces are so cool that most hydrogen is in the ground state.

Astronomers use the term nebula to refer to

Astronomers use the term nebula to refer to



a) outer envelopes of dying stars that drift gently into space.
b) remnants of stars that die by supernova.
c) clouds of gas and dust in interstellar space.
d) distant galaxies seen beyond our Milky Way.
e) All of the above are correct.


Answer: e) All of the above are correct.

Nebula refers to any fuzzy patch - bright or dark - in the sky.

Solar energy is produced by

Solar energy is produced by




a) the release of heat leftover from the Sun's formation.
b) solar magnetism.
c) fission of heavier nuclei into lighter ones.
d) fusion of light nuclei into heavier ones.


Answer: d) fusion of light nuclei into heavier ones.

Protons stick together to form a new element, the element is lighter and energy is given off in the process

The proton-proton cycle involves what kind of fusion process?

The proton-proton cycle involves what kind of fusion process?



a) carbon (C) into oxygen (O)
b) helium (He) into carbon (C)
c) hydrogen (H) into helium (He)
d) neon (Ne) into silicon (Si)
e) oxygen (O) into iron (Fe)


Answer: c) hydrogen (H) into helium (He)

In the P-P cycle, four hydrogen nuclei (protons) fuse into one helium nucleus, releasing gamma rays and neutrinos

What is probably responsible for the increase in temperature of the corona far from the Sun's surface?

What is probably responsible for the increase in temperature of the corona far from the Sun's surface?



a) the higher rate of fusion
b) the Sun's magnetism
c) higher radiation pressures
d) absorption of X rays
e) convection currents


Answer: b) the Sun's magnetism


Apparently the Sun's magnetic field acts like a pump to increase the speeds of particles in the upper corona.

Sunspots appear dark because they are

Sunspots appear dark because they are



a) holes in the photosphere through which you can see deeply into the solar interior.
b) a bit cooler, thus dimmer than the rest of the photosphere.
c) large opaque structures that block light from the glowing solar surface.
d) causing retinal damage.


Answer: b) a bit cooler, thus dimmer than the rest of the photosphere.

The photosphere (the visible surface) of the Sun is like

The photosphere (the visible surface) of the Sun is like




a) the surface of Earth; you could stand on it, if you could survive the heat.
b) the surface of the ocean; you couldn't stand on it, but you would clearly be able to detect differences above and below it.
c) an apparent surface; you would notice very little change as you go through it, as when you fly through a cloud.
d) the surface of a trampoline; you could land on it, but the intense pressure would push you away again.


Answer: c) an apparent surface; you would notice very little change as you go through it, as when you fly through a cloud.

The visible light we see comes from the photosphere - creating the appearance of a sharp edge, or surface, to the Sun.

The light from the East limb (edge) of the Sun is blue shifted and the light from the West limb is redshifted. This is because

The light from the East limb (edge) of the Sun is blue shifted and the light from the West limb is redshifted. This is because



a) different kinds of atoms emit light at the opposite edges.
b) the Sun is rotating.
c) the distance from the Sun to Earth changes.
d) the two sides of the Sun are at different temperatures.


Answer: b) the Sun is rotating.

One edge is a "source moving towards" us and the other edge is a "source moving away" from us.

Tremendous pressure is created at the Sun's center due to its own gravity. The Sun is kept from collapsing by

Tremendous pressure is created at the Sun's center due to its own gravity. The Sun is kept from collapsing by



a) neutrinos and other particles generated by nuclear fusion.
b) a hard inner core.
c) gas pressure created by the heat of nuclear fusion.
d) gas pressure created from left over heat from the formation of the Sun.


Answer: c) gas pressure created by the heat of nuclear fusion.

The density of the Sun is most similar to that of

The density of the Sun is most similar to that of



a) a comet.
b) Jupiter.
c) Earth.
d) interstellar gas.
e) an asteroid.


Answer: B) Jupiter

The Sun is a ball of charged gas, without a solid surface. Jupiter has a similar composition, but not enough mass to be a star.

Star formation happens when part of a dust cloud begins to contract under its own gravitational force stars are formed from cold interstellar gas clouds made up of

Star formation happens when part of a dust cloud begins to contract under its own gravitational force stars are formed from cold interstellar gas clouds made up of



a) atomic gas of mostly hydrogen, oxygen, carbon, and nitrogen
b) molecular hydrogen gas and dust grains
c) some hydrogen gas, comets, and astroids
d) stars are formed from ver HOT gas


Answer: b) molecular hydrogen gas and dust grains

The reddish color of emission nebulae indicates that

The reddish color of emission nebulae indicates that 



A) gas and dust is moving away from the earth
B) hydrogen gas is present
C) dying stars have recently exploded
D) cool red stars are hidden inside
E) dust is present


Answer: B) hydrogen gas is present

Glowing hydrogen gas emits red light around the Horsehead nebula

Some regions of the milky way's disk appear dark because

Some regions of the milky way's disk appear dark because



a) there are no stars here
b) stars in that direction are obscured by interstellar gas
c) numerous black holes absorb the light
b) stars in that direction are obscured by interstellar dust


Answer: dust grains are about the same size as visible light, and they can scatter or block the shorter wavelengths.

Interstellar gas is composed primarily of

Interstellar gas is composed primarily of



a) 90% hydrogen, 9% helium, and 1% Heavier gas
b) molecules including water and CO2.
c) 50% hydrogen, 50% helium.
d) hydrogen, oxygen, and nitrogen.
e) 99% hydrogen, and 1% heavier elements.


Answer: a) 90% hydrogen, 9% helium, and 1% Heavier gas

The composition of interstellar gas mirrors that of the Sun, stars, and the Jovian planets.